$$(17-2x)\cdot(11-2x)x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 11 }{ 2 } & x_3 = \dfrac{ 17 }{ 2 } \end{matrix} $$
Explanation
$$ \begin{aligned} (17-2x)\cdot(11-2x)x &= 0&& \text{simplify left side} \\[1 em](187-34x-22x+4x^2)x &= 0&& \\[1 em](4x^2-56x+187)x &= 0&& \\[1 em]4x^3-56x^2+187x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 4x^{3}-56x^{2}+187x = 0 } $, first we need to factor our $ x $.
$$ 4x^{3}-56x^{2}+187x = x \left( 4x^{2}-56x+187 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 4x^{2}-56x+187 = 0$.
$ 4x^{2}-56x+187 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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