$$12x^2+6x-4-(7x^2+11x+8) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 265 }}{ 10 } & x_2 = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 265 }}{ 10 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 12x^2+6x-4-(7x^2+11x+8) &= 0&& \text{simplify left side} \\[1 em]12x^2+6x-4-7x^2-11x-8 &= 0&& \\[1 em]5x^2-5x-12 &= 0&& \\[1 em] \end{aligned} $$
$ 5x^{2}-5x-12 = 0 $ is a quadratic equation.
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