$$(12t-5)(12t+5) = 0$$
Answer
$$ \begin{matrix}t_1 = \dfrac{ 5 }{ 12 } & t_2 = -\dfrac{ 5 }{ 12 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (12t-5)(12t+5) &= 0&& \text{simplify left side} \\[1 em]144t^2+60t-60t-25 &= 0&& \\[1 em]144t^2+60t-60t-25 &= 0&& \\[1 em]144t^2-25 &= 0&& \\[1 em] \end{aligned} $$
$ 144x^{2}-25 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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