$$10x+10-(7x^2+5x-8) = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = -\dfrac{ 9 }{ 7 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 10x+10-(7x^2+5x-8) &= 0&& \text{simplify left side} \\[1 em]10x+10-7x^2-5x+8 &= 0&& \\[1 em]-7x^2+5x+18 &= 0&& \\[1 em] \end{aligned} $$
$ -7x^{2}+5x+18 = 0 $ is a quadratic equation.
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