$$\frac{100x^2+201x+140}{4x+7} = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 201 }{ 200 }+\dfrac{\sqrt{ 15599 }}{ 200 }i & x_2 = -\dfrac{ 201 }{ 200 }-\dfrac{\sqrt{ 15599 }}{ 200 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{100x^2+201x+140}{4x+7} &= 0&& \text{multiply ALL terms by } \color{blue}{ 4x+7 }. \\[1 em](4x+7)\frac{100x^2+201x+140}{4x+7} &= (4x+7)\cdot0&& \text{cancel out the denominators} \\[1 em]100x^2+201x+140 &= 0&& \\[1 em] \end{aligned} $$
$ 100x^{2}+201x+140 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver