$$-x\cdot2-4x+1-(2x\cdot2+9) = 0$$
Answer
$$ x = -\frac{4}{5} $$
Explanation
$$ \begin{aligned} -x\cdot2-4x+1-(2x\cdot2+9) &= 0&& \text{simplify left side} \\[1 em]-6x+1-(4x+9) &= 0&& \\[1 em]-6x+1-4x-9 &= 0&& \\[1 em]-10x-8 &= 0&& \text{ move the constants to the right } \\[1 em]-10x &= 8&& \text{ divide both sides by $ -10 $ } \\[1 em]x &= -\frac{8}{10}&& \\[1 em]x &= -\frac{4}{5}&& \\[1 em] \end{aligned} $$
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