$$(-5d+8)(d-3) = 0$$
Answer
$$ \begin{matrix}d_1 = 3 & d_2 = \dfrac{ 8 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (-5d+8)(d-3) &= 0&& \text{simplify left side} \\[1 em]-5d^2+15d+8d-24 &= 0&& \\[1 em]-5d^2+23d-24 &= 0&& \\[1 em] \end{aligned} $$
$ -5x^{2}+23x-24 = 0 $ is a quadratic equation.
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