$$\frac{169}{25}x^2-\frac{7286}{25}x+\frac{17338}{5} = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 3643 }{ 169 }+\dfrac{\sqrt{ 1379161 }}{ 169 }i & x_2 = \dfrac{ 3643 }{ 169 }-\dfrac{\sqrt{ 1379161 }}{ 169 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{169}{25}x^2-\frac{7286}{25}x+\frac{17338}{5} &= 0&& \text{multiply ALL terms by } \color{blue}{ 25 }. \\[1 em]25 \cdot \frac{169}{25}x^2-25\frac{7286}{25}x+25\cdot\frac{17338}{5} &= 25\cdot0&& \text{cancel out the denominators} \\[1 em]169x^2-7286x+86690 &= 0&& \\[1 em] \end{aligned} $$
$ 169x^{2}-7286x+86690 = 0 $ is a quadratic equation.
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