Find Least Common Multiple of 142, 256 and 482 using division method..
Answer
LCM( 142, 256, 482 ) = 4380416
Explanation
Step 1 : Write the given numbers in a horizontal line.
| 142 | 256 | 482 |
Step 2 : Divide the given numbers by smallest prime number. In this example we can divide by 2.
(if any number is not divisible by 2, write it down unchanged)
| 2 | 142 | 256 | 482 |
| 71 | 128 | 241 |
Step 3 : Continue dividing by prime numbers till we get 1 in all columns.
| 2 | 142 | 256 | 482 |
| 2 | 71 | 128 | 241 |
| 2 | 71 | 64 | 241 |
| 2 | 71 | 32 | 241 |
| 2 | 71 | 16 | 241 |
| 2 | 71 | 8 | 241 |
| 2 | 71 | 4 | 241 |
| 2 | 71 | 2 | 241 |
| 71 | 71 | 1 | 241 |
| 241 | 1 | 1 | 241 |
| 1 | 1 | 1 |
Step 4 : Multiply numbers in first column to get LCM.
LCM( 142, 256, 482 ) = 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 71 · 241 = 4380416 .
This solution can be visualized using a Venn diagram.
The LCM is equal to the product of all the numbers on the diagram.
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