Answer
$$ \displaystyle\int {x}^{2}{\cdot}{\mathrm{e}}^{{x}^{3+1}}\, \mathrm d x = -{{\Gamma\left({{3}\over{4}} , -x^4\right)\,x}\over{4\,\left(-1 \right)^{{{3}\over{4}}}\,\left| x\right| }} $$
Explanation
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