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Answer
$$ \displaystyle\int {\left(\tan\left(3x\right)\right)}^{6}\, \mathrm d x = {{3\,\tan ^5\left(3\,x\right)-5\,\tan ^3\left(3\,x\right)+15\,\tan \left(3\,x\right)-45\,x}\over{45}} $$
Explanation
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