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Answer
$$ \displaystyle\int \ln\left({x}^{2}-4x+5\right)-0.2x\, \mathrm d x = {{10\,x\,\ln \left(x^2-4\,x+5\right)-20\,\ln \left(x^2-4\,x+5 \right)-x^2-20\,x+20\,\arctan \left(x-2\right)}\over{10}} $$
Explanation
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