Answer
$$ = -{{11\,\sqrt{6}\,\ln \left(2\,x^2+3\right)-15\,\sqrt{6}\,\ln \left(2\,x-1\right)-7\,\sqrt{6}\,\ln \left(2\,x-3\right)+36\, \arctan \left({{2\,x}\over{\sqrt{6}}}\right)}\over{70\,6^{{{3}\over{ 2}}}}} $$
Explanation
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