Answer
$$ = {{10\,x+12\,x^{{{5}\over{6}}}+15\,x^{{{2}\over{3}}}+20\,\sqrt{x}+30 \,x^{{{1}\over{3}}}+60\,x^{{{1}\over{6}}}+60\,\ln \left(x^{{{1 }\over{6}}}-1\right)}\over{10}} $$
Explanation
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