Answer
$$ \displaystyle\int \dfrac{{\left(\sqrt{x}-3\right)}^{5}}{2{\cdot}\sqrt{x}}\, \mathrm d x = {{x^3-18\,x^{{{5}\over{2}}}+135\,x^2-540\,x^{{{3}\over{2}}}+1215\,x -1458\,\sqrt{x}+729}\over{6}} $$
Explanation
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