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Answer
$$ \displaystyle\int \dfrac{\sec\left(4x\right){\cdot}\sec\left(4x\right)}{2{\cdot}\tan\left(4x\right)-5}\, \mathrm d x = {{\ln \left(2\,\tan \left(4\,x\right)-5\right)}\over{8}} $$
Explanation
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