Answer
$$ \displaystyle\int \left(2x-3\right){\cdot}\sin\left(2x\right)\, \mathrm d x = {{\sin \left(2\,x\right)-2\,x\,\cos \left(2\,x\right)+3\,\cos \left(2\,x\right)}\over{2}} $$
Explanation
This page was created using
Integral Calculator