Answer
$$ = {{4\,\sqrt{6}\,\ln \left(3\,x^2+2\right)-3\,\sqrt{6}\,\ln \left(x +1\right)+21\,\arctan \left({{3\,x}\over{\sqrt{6}}}\right)-15\, \sqrt{6}\,x}\over{45\,\sqrt{6}}} $$
Explanation
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