STEP 1: find side $ a $
To find side $ a $ use formula:
$$ r = \dfrac{ \sqrt{ 3 } \cdot a }{ 2 } $$After substituting $ r = 6 \sqrt{ 3 } $ we have:
$$ 6 \sqrt{ 3 } = \dfrac{ \sqrt{ 3 } \cdot a }{ 2 } $$ $$ \sqrt{ 3 } \cdot a = 6 \sqrt{ 3 } \cdot 2 $$ $$ \sqrt{ 3 } \cdot a = 12 \sqrt{ 3 } $$ $$ a = \dfrac{ 12 \sqrt{ 3 } }{ \sqrt{ 3 } } $$ $$ a = 12 $$STEP 2: find area $ A $
To find area $ A $ use formula:
$$ A = \dfrac{ 3 \sqrt{ 3 } \cdot a^2 }{ 2 } $$After substituting $ a = 12 $ we have:
$$ A = \dfrac{ 3 \sqrt{ 3 } \cdot 12^2 }{ 2 } $$ $$ A = \dfrac{ 3 \sqrt{ 3 } \cdot 144 }{ 2 }$$ $$ A = \dfrac{ 432 \sqrt{ 3 } }{ 2 }$$ $$ A = 216 \sqrt{ 3 } $$