Find the area $ A $ of a hexagon if short diagonal $s = 8$.

$A = 32 \sqrt{ 3 }$

STEP 1: find side $ a $

To find side $ a $ use formula:

$$ s = \sqrt{ 3 } \cdot a $$

After substituting $ s = 8 $ we have:

$$ 8 = \sqrt{ 3 } \cdot a $$ $$ a = \dfrac{ 8 }{ \sqrt{ 3 } } $$ $$ a = \frac{ 8 \sqrt{ 3}}{ 3 } $$

STEP 2: find area $ A $

To find area $ A $ use formula:

$$ A = \dfrac{ 3 \sqrt{ 3 } \cdot a^2 }{ 2 } $$

After substituting $ a = \frac{ 8 \sqrt{ 3}}{ 3 } $ we have:

$$ A = \dfrac{ 3 \sqrt{ 3 } \cdot \left( \frac{ 8 \sqrt{ 3}}{ 3 } \right)^2 }{ 2 } $$ $$ A = \dfrac{ 3 \sqrt{ 3 } \cdot \frac{ 64 }{ 3 } }{ 2 }$$ $$ A = \dfrac{ 64 \sqrt{ 3 } }{ 2 }$$ $$ A = 32 \sqrt{ 3 } $$

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