Find the area $ A $ of a hexagon if short diagonal $s = \frac{ 3 }{ 2 }$.

$A = \frac{ 9 \sqrt{ 3}}{ 8 }$

STEP 1: find side $ a $

To find side $ a $ use formula:

$$ s = \sqrt{ 3 } \cdot a $$

After substituting $ s = \frac{ 3 }{ 2 } $ we have:

$$ \frac{ 3 }{ 2 } = \sqrt{ 3 } \cdot a $$ $$ a = \dfrac{ \frac{ 3 }{ 2 } }{ \sqrt{ 3 } } $$ $$ a = \frac{\sqrt{ 3 }}{ 2 } $$

STEP 2: find area $ A $

To find area $ A $ use formula:

$$ A = \dfrac{ 3 \sqrt{ 3 } \cdot a^2 }{ 2 } $$

After substituting $ a = \frac{\sqrt{ 3 }}{ 2 } $ we have:

$$ A = \dfrac{ 3 \sqrt{ 3 } \cdot \left( \frac{\sqrt{ 3 }}{ 2 } \right)^2 }{ 2 } $$ $$ A = \dfrac{ 3 \sqrt{ 3 } \cdot \frac{ 3 }{ 4 } }{ 2 }$$ $$ A = \dfrac{ \frac{ 9 \sqrt{ 3}}{ 4 } }{ 2 }$$ $$ A = \frac{ 9 \sqrt{ 3}}{ 8 } $$

Hexagon Calculator