Find the side $ a $ of a hexagon if short diagonal $s = \frac{ 41 }{ 50 }$.
Answer
$a = \frac{ 41 \sqrt{ 3}}{ 150 }$
Explanation
To find side $ a $ use formula:
$$ s = \sqrt{ 3 } \cdot a $$After substituting $ s = \frac{ 41 }{ 50 } $ we have:
$$ \frac{ 41 }{ 50 } = \sqrt{ 3 } \cdot a $$ $$ a = \dfrac{ \frac{ 41 }{ 50 } }{ \sqrt{ 3 } } $$ $$ a = \frac{ 41 \sqrt{ 3}}{ 150 } $$This page was created using
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