Find Greatest Common Divisor of 9800, 420 and 2520, using repeated division.
Answer
The GCD of given numbers is 20.
Explanation
Step 1 : Place the numbers inside division bar:.
| 9800 | 420 | 2520 |
Step 2 : Divide numbers by 2.
| 2 | 9800 | 420 | 2520 |
| 4900 | 210 | 1260 |
Step 3 : Divide numbers by 2.
| 2 | 9800 | 420 | 2520 |
| 2 | 4900 | 210 | 1260 |
| 2450 | 105 | 630 |
Step 4 : Divide numbers by 5.
| 2 | 9800 | 420 | 2520 |
| 2 | 4900 | 210 | 1260 |
| 5 | 2450 | 105 | 630 |
| 490 | 21 | 126 |
Step 5 : Number 490, 21 and 126, cannot be divided any more. The GCD is:
$$ GCD = 2\cdot2\cdot5 = 20 $$This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.
This page was created using
GCD Calculator