The GCD of given numbers is 121.
Step 1 : Find prime factorization of each number.
$$\begin{aligned}242 =& 2\cdot11\cdot11\\[8pt]484 =& 2\cdot2\cdot11\cdot11\\[8pt]363 =& 3\cdot11\cdot11\\[8pt]\end{aligned}$$(view steps on how to factor 242, 484 and 363. )
Step 2 : Put a box around factors that are common for all numbers:
$$\begin{aligned}242 =& 2\cdot\color{blue}{\boxed{11}}\cdot\color{red}{\boxed{11}}\\[8pt]484 =& 2\cdot2\cdot\color{blue}{\boxed{11}}\cdot\color{red}{\boxed{11}}\\[8pt]363 =& 3\cdot\color{blue}{\boxed{11}}\cdot\color{red}{\boxed{11}}\\[8pt]\end{aligned}$$Step 3 : Multiply the boxed numbers together:
$$ GCD = 11\cdot11 = 121 $$This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.