The GCD of given numbers is 1.
Step 1 :
Divide $ 889 $ by $ 246 $ and get the remainder
The remainder is positive ($ 151 > 0 $), so we will continue with division.
Step 2 :
Divide $ 246 $ by $ \color{blue}{ 151 } $ and get the remainder
The remainder is still positive ($ 95 > 0 $), so we will continue with division.
Step 3 :
Divide $ 151 $ by $ \color{blue}{ 95 } $ and get the remainder
The remainder is still positive ($ 56 > 0 $), so we will continue with division.
Step 4 :
Divide $ 95 $ by $ \color{blue}{ 56 } $ and get the remainder
The remainder is still positive ($ 39 > 0 $), so we will continue with division.
Step 5 :
Divide $ 56 $ by $ \color{blue}{ 39 } $ and get the remainder
The remainder is still positive ($ 17 > 0 $), so we will continue with division.
Step 6 :
Divide $ 39 $ by $ \color{blue}{ 17 } $ and get the remainder
The remainder is still positive ($ 5 > 0 $), so we will continue with division.
Step 7 :
Divide $ 17 $ by $ \color{blue}{ 5 } $ and get the remainder
The remainder is still positive ($ 2 > 0 $), so we will continue with division.
Step 8 :
Divide $ 5 $ by $ \color{blue}{ 2 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 9 :
Divide $ 2 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
889 | : | 246 | = | 3 | remainder ( 151 ) | ||||||||||||||||
246 | : | 151 | = | 1 | remainder ( 95 ) | ||||||||||||||||
151 | : | 95 | = | 1 | remainder ( 56 ) | ||||||||||||||||
95 | : | 56 | = | 1 | remainder ( 39 ) | ||||||||||||||||
56 | : | 39 | = | 1 | remainder ( 17 ) | ||||||||||||||||
39 | : | 17 | = | 2 | remainder ( 5 ) | ||||||||||||||||
17 | : | 5 | = | 3 | remainder ( 2 ) | ||||||||||||||||
5 | : | 2 | = | 2 | remainder ( 1 ) | ||||||||||||||||
2 | : | 1 | = | 2 | remainder ( 0 ) | ||||||||||||||||
GCD = 1 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.