The GCD of given numbers is 1.
Step 1 :
Divide $ 97 $ by $ 69 $ and get the remainder
The remainder is positive ($ 28 > 0 $), so we will continue with division.
Step 2 :
Divide $ 69 $ by $ \color{blue}{ 28 } $ and get the remainder
The remainder is still positive ($ 13 > 0 $), so we will continue with division.
Step 3 :
Divide $ 28 $ by $ \color{blue}{ 13 } $ and get the remainder
The remainder is still positive ($ 2 > 0 $), so we will continue with division.
Step 4 :
Divide $ 13 $ by $ \color{blue}{ 2 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 5 :
Divide $ 2 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
97 | : | 69 | = | 1 | remainder ( 28 ) | ||||||||
69 | : | 28 | = | 2 | remainder ( 13 ) | ||||||||
28 | : | 13 | = | 2 | remainder ( 2 ) | ||||||||
13 | : | 2 | = | 6 | remainder ( 1 ) | ||||||||
2 | : | 1 | = | 2 | remainder ( 0 ) | ||||||||
GCD = 1 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.