The GCD of given numbers is 1.
Step 1 :
Divide by and get the remainder
The remainder is positive (), so we will continue with division.
Step 2 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 3 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 4 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 5 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 6 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 7 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 8 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 9 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 10 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 11 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 12 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 13 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 14 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 15 :
Divide by and get the remainder
The remainder is zero => GCD is the last divisor .
We can summarize an algorithm into a following table.
11155 | : | 6897 | = | 1 | remainder ( 4258 ) | ||||||||||||||||||||||||||||
6897 | : | 4258 | = | 1 | remainder ( 2639 ) | ||||||||||||||||||||||||||||
4258 | : | 2639 | = | 1 | remainder ( 1619 ) | ||||||||||||||||||||||||||||
2639 | : | 1619 | = | 1 | remainder ( 1020 ) | ||||||||||||||||||||||||||||
1619 | : | 1020 | = | 1 | remainder ( 599 ) | ||||||||||||||||||||||||||||
1020 | : | 599 | = | 1 | remainder ( 421 ) | ||||||||||||||||||||||||||||
599 | : | 421 | = | 1 | remainder ( 178 ) | ||||||||||||||||||||||||||||
421 | : | 178 | = | 2 | remainder ( 65 ) | ||||||||||||||||||||||||||||
178 | : | 65 | = | 2 | remainder ( 48 ) | ||||||||||||||||||||||||||||
65 | : | 48 | = | 1 | remainder ( 17 ) | ||||||||||||||||||||||||||||
48 | : | 17 | = | 2 | remainder ( 14 ) | ||||||||||||||||||||||||||||
17 | : | 14 | = | 1 | remainder ( 3 ) | ||||||||||||||||||||||||||||
14 | : | 3 | = | 4 | remainder ( 2 ) | ||||||||||||||||||||||||||||
3 | : | 2 | = | 1 | remainder ( 1 ) | ||||||||||||||||||||||||||||
2 | : | 1 | = | 2 | remainder ( 0 ) | ||||||||||||||||||||||||||||
GCD = 1 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.