The GCD of given numbers is 1.
Step 1 :
Divide $ 419 $ by $ 105 $ and get the remainder
The remainder is positive ($ 104 > 0 $), so we will continue with division.
Step 2 :
Divide $ 105 $ by $ \color{blue}{ 104 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 3 :
Divide $ 104 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
419 | : | 105 | = | 3 | remainder ( 104 ) | ||||
105 | : | 104 | = | 1 | remainder ( 1 ) | ||||
104 | : | 1 | = | 104 | remainder ( 0 ) | ||||
GCD = 1 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.