The GCD of given numbers is 1.
Step 1 :
Divide $ 314 $ by $ 159 $ and get the remainder
The remainder is positive ($ 155 > 0 $), so we will continue with division.
Step 2 :
Divide $ 159 $ by $ \color{blue}{ 155 } $ and get the remainder
The remainder is still positive ($ 4 > 0 $), so we will continue with division.
Step 3 :
Divide $ 155 $ by $ \color{blue}{ 4 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 4 :
Divide $ 4 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 5 :
Divide $ 3 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
314 | : | 159 | = | 1 | remainder ( 155 ) | ||||||||
159 | : | 155 | = | 1 | remainder ( 4 ) | ||||||||
155 | : | 4 | = | 38 | remainder ( 3 ) | ||||||||
4 | : | 3 | = | 1 | remainder ( 1 ) | ||||||||
3 | : | 1 | = | 3 | remainder ( 0 ) | ||||||||
GCD = 1 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.