The GCD of given numbers is 2.
Step 1 :
Divide by and get the remainder
The remainder is positive (), so we will continue with division.
Step 2 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 3 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 4 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 5 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 6 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 7 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 8 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 9 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 10 :
Divide by and get the remainder
The remainder is still positive (), so we will continue with division.
Step 11 :
Divide by and get the remainder
The remainder is zero => GCD is the last divisor .
We can summarize an algorithm into a following table.
1970 | : | 1066 | = | 1 | remainder ( 904 ) | ||||||||||||||||||||
1066 | : | 904 | = | 1 | remainder ( 162 ) | ||||||||||||||||||||
904 | : | 162 | = | 5 | remainder ( 94 ) | ||||||||||||||||||||
162 | : | 94 | = | 1 | remainder ( 68 ) | ||||||||||||||||||||
94 | : | 68 | = | 1 | remainder ( 26 ) | ||||||||||||||||||||
68 | : | 26 | = | 2 | remainder ( 16 ) | ||||||||||||||||||||
26 | : | 16 | = | 1 | remainder ( 10 ) | ||||||||||||||||||||
16 | : | 10 | = | 1 | remainder ( 6 ) | ||||||||||||||||||||
10 | : | 6 | = | 1 | remainder ( 4 ) | ||||||||||||||||||||
6 | : | 4 | = | 1 | remainder ( 2 ) | ||||||||||||||||||||
4 | : | 2 | = | 2 | remainder ( 0 ) | ||||||||||||||||||||
GCD = 2 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.