The GCD of given numbers is 41.
Step 1 :
Divide $ 451 $ by $ 123 $ and get the remainder
The remainder is positive ($ 82 > 0 $), so we will continue with division.
Step 2 :
Divide $ 123 $ by $ \color{blue}{ 82 } $ and get the remainder
The remainder is still positive ($ 41 > 0 $), so we will continue with division.
Step 3 :
Divide $ 82 $ by $ \color{blue}{ 41 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 41 }} $.
We can summarize an algorithm into a following table.
451 | : | 123 | = | 3 | remainder ( 82 ) | ||||
123 | : | 82 | = | 1 | remainder ( 41 ) | ||||
82 | : | 41 | = | 2 | remainder ( 0 ) | ||||
GCD = 41 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.