The GCD of given numbers is 3.
Step 1 :
Divide $ 297 $ by $ 123 $ and get the remainder
The remainder is positive ($ 51 > 0 $), so we will continue with division.
Step 2 :
Divide $ 123 $ by $ \color{blue}{ 51 } $ and get the remainder
The remainder is still positive ($ 21 > 0 $), so we will continue with division.
Step 3 :
Divide $ 51 $ by $ \color{blue}{ 21 } $ and get the remainder
The remainder is still positive ($ 9 > 0 $), so we will continue with division.
Step 4 :
Divide $ 21 $ by $ \color{blue}{ 9 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 5 :
Divide $ 9 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 3 }} $.
We can summarize an algorithm into a following table.
297 | : | 123 | = | 2 | remainder ( 51 ) | ||||||||
123 | : | 51 | = | 2 | remainder ( 21 ) | ||||||||
51 | : | 21 | = | 2 | remainder ( 9 ) | ||||||||
21 | : | 9 | = | 2 | remainder ( 3 ) | ||||||||
9 | : | 3 | = | 3 | remainder ( 0 ) | ||||||||
GCD = 3 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.