The GCD of given numbers is 11.
Step 1 :
Divide $ 1331 $ by $ 1001 $ and get the remainder
The remainder is positive ($ 330 > 0 $), so we will continue with division.
Step 2 :
Divide $ 1001 $ by $ \color{blue}{ 330 } $ and get the remainder
The remainder is still positive ($ 11 > 0 $), so we will continue with division.
Step 3 :
Divide $ 330 $ by $ \color{blue}{ 11 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 11 }} $.
We can summarize an algorithm into a following table.
1331 | : | 1001 | = | 1 | remainder ( 330 ) | ||||
1001 | : | 330 | = | 3 | remainder ( 11 ) | ||||
330 | : | 11 | = | 30 | remainder ( 0 ) | ||||
GCD = 11 |
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.