To find circumradius $ R $ use formula:
$$ R = \dfrac{ \sqrt{ 3 } \cdot a }{ 3 } $$After substituting $ a = \frac{ 47 }{ 2 } $ we have:
$$ R = \dfrac{ \sqrt{ 3 } \cdot \frac{ 47 }{ 2 } }{ 3 } $$$$ R = \dfrac{ \frac{ 47 \sqrt{ 3}}{ 2 } }{ 3 } $$ $$ R = \frac{ 47 \sqrt{ 3}}{ 6 } $$