Find the area $ A $ of an equilateral triangle if side $a = 6 \sqrt{ 2 }$.
Answer
$A = 18 \sqrt{ 3 }$
Explanation
To find area $ A $ use formula:
$$ A = \dfrac{ \sqrt{ 3 } \cdot a^2 }{ 4 } $$After substituting $ a = 6 \sqrt{ 2 } $ we have:
$$ A = \dfrac{ \sqrt{ 3 } \cdot \left(6 \sqrt{ 2 }\right)^2 }{ 4 } $$ $$ A = \dfrac{ \sqrt{ 3 } \cdot 72 }{ 4 }$$ $$ A = \dfrac{ 72 \sqrt{ 3 } }{ 4 }$$ $$ A = 18 \sqrt{ 3 } $$This page was created using
Equilateral Triangle Calculator