To find area $ A $ use formula:
$$ A = \dfrac{ \sqrt{ 3 } \cdot a^2 }{ 4 } $$After substituting $ a = 6 $ we have:
$$ A = \dfrac{ \sqrt{ 3 } \cdot 6^2 }{ 4 } $$ $$ A = \dfrac{ \sqrt{ 3 } \cdot 36 }{ 4 }$$ $$ A = \dfrac{ 36 \sqrt{ 3 } }{ 4 }$$ $$ A = 9 \sqrt{ 3 } $$