Find eigenvalues of matrix:
$A = [0410]$

Answer

The eigenvalues of matrix A are:
$λ_{1} = 2 and λ_{2} = - 2$

Explanation

Step 1 : The characteristic polynomial for matrix A is:

p (λ) = λ^{2} - 4

Step 2 : Eigenvalues are roots of the characteristic polynomial, so the equation

λ^{2} - 4 = 0

yields the above eigenvalues.

( click here to view an explanation on how to solve this equation.)

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Find eigenvalues of matrix: A=[04​10​]

The eigenvalues of matrix A are: λ1​=2 and λ2​=−2

Find eigenvalues of matrix:
$A = [0410]$

The eigenvalues of matrix A are:
$λ_{1} = 2 and λ_{2} = - 2$