The modulus of $ z $ is:
$$ |z| = 2 \sqrt{ 17 }$$To find modulus of a complex number $ z = a + bi $ we use formula:
$$ |z| = \sqrt{a^2 + b^2} $$In this example we have $ a = 8 $ and $ b = -2 $ so:
$$ \begin{aligned}|z| &= \sqrt{ 8^2 + (-2)^2 } \\[1 em]|z| &= \sqrt{ 64 + 4 } \\[1 em]|z| &= \sqrt{ 68 } \\[1 em]|z| &= 2 \sqrt{ 17 } \\[1 em] \end{aligned} $$