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Answer

$$\frac{x^2}{75}-\frac{1}{3}=\frac{x^2-25}{75}$$

Explanation

$$ \begin{aligned}\frac{x^2}{75}-\frac{1}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^2-25}{75}\end{aligned} $$
①

Subtract $ \dfrac{1}{3} $ from $ \dfrac{x^2}{75} $ to get $ \dfrac{ \color{purple}{ x^2-25 } }{ 75 }$.

To subtract raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the second fraction by $\color{blue}{25}$.

$$ \begin{aligned} \frac{x^2}{75} - \frac{1}{3} & = \frac{ x^2 }{ 75 } - \frac{ 1 \cdot \color{blue}{ 25 }}{ 3 \cdot \color{blue}{ 25 }} = \\[1ex] &=\frac{ \color{purple}{ x^2 } }{ 75 } - \frac{ \color{purple}{ 25 } }{ 75 }=\frac{ \color{purple}{ x^2-25 } }{ 75 } \end{aligned} $$
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