Question
Answer
$$sqrt\cdot8e^{4.5pii}\cdot(1+j)=sqrt\cdot8e^{4i^2p}\cdot(1+j)$$
Explanation
| $$ \begin{aligned}sqrt\cdot8e^{4.5pii}\cdot(1+j)& \xlongequal{ }sqrt\cdot8e^{4pii}\cdot(1+j) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}sqrt\cdot8e^{4i^2p}\cdot(1+j)\end{aligned} $$ | |
| ① | $$ 4 p i i = 4 i^{1 + 1} p = 4 i^2 p $$ |
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