$8 \cdot \frac{i}{- 1 + 3 i} = \frac{- 8 i + 24}{10}$

Explanation

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$8 \cdot \frac{i}{- 1 + 3 i} \overset{◯}{1} 8 \cdot \frac{3 - i}{10} \overset{◯}{2} \frac{- 8 i + 24}{10}$
①	Divide $i$ by $- 1 + 3 i$ to get $\frac{3 - i}{10}$ . ( view steps )
②	Multiply $8$ by $\frac{3 - i}{10}$ to get $\frac{- 8 i + 24}{10}$ . Step 1: Write $8$ as a fraction by putting $1$ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $8 \cdot \frac{3 - i}{10} Step 1 \frac{8}{1} \cdot \frac{3 - i}{10} Step 2 \frac{8 \cdot ( 3 - i )}{1 \cdot 10} = Step 3 \frac{24 - 8 i}{10} = \frac{- 8 i + 24}{10}$

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8⋅−1+3ii​=10−8i+24​

$8 \cdot \frac{i}{- 1 + 3 i} = \frac{- 8 i + 24}{10}$