Answer
$$-5(-2i)\cdot(2-3i)=20i+30$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-5(-2i)\cdot(2-3i)& \xlongequal{ }--10i\cdot(2-3i) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(-20i+30i^2) \xlongequal{ } \\[1 em] & \xlongequal{ }-(-20i-30) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}20i+30\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{-10i} $ by $ \left( 2-3i\right) $ $$ \color{blue}{-10i} \cdot \left( 2-3i\right) = -20i+30i^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-20i-30 \right) = 20i+30 $$ |
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