$(x - (4 + 3 i)) (x - (4 - 3 i)) = - 9 i^{2} + x^{2} - 8 x + 16$

Explanation

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$(x - (4 + 3 i)) (x - (4 - 3 i)) \overset{◯}{1} (x - 4 - 3 i) (x - 4 + 3 i) \overset{◯}{2} \overset{◯}{3} - 9 i^{2} + x^{2} - 8 x + 16$
①	Remove the parentheses by changing the sign of each term within them. $- (4 + 3 i) = - 4 - 3 i$ Remove the parentheses by changing the sign of each term within them. $- (4 - 3 i) = - 4 + 3 i$
②	Multiply each term of $(x - 4 - 3 i)$ by each term in $(x - 4 + 3 i)$ . $(x - 4 - 3 i) \cdot (x - 4 + 3 i) = = x^{2} - 4 x + 3 i x - 4 x + 16 - 12 i - 3 i x + 12 i - 9 i^{2}$
③	Combine like terms: $x^{2} - 4 x + 3 i x - 4 x + 16 - 12 i - 3 i x + 12 i - 9 i^{2} = - 9 i^{2} + x^{2} - 8 x + 16$

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(x−(4+3i))(x−(4−3i))=−9i2+x2−8x+16

$(x - (4 + 3 i)) (x - (4 - 3 i)) = - 9 i^{2} + x^{2} - 8 x + 16$