$(9 + 7 i) \cdot (6 + i) = 7 i^{2} + 51 i + 54$

Explanation

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$(9 + 7 i) \cdot (6 + i) \overset{◯}{1} 54 + 9 i + 42 i + 7 i^{2} \overset{◯}{2} 7 i^{2} + 51 i + 54$
①	Multiply each term of $(9 + 7 i)$ by each term in $(6 + i)$ . $(9 + 7 i) \cdot (6 + i) = 54 + 9 i + 42 i + 7 i^{2}$
②	Combine like terms: $54 + 9 i + 42 i + 7 i^{2} = 7 i^{2} + 51 i + 54$

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(9+7i)⋅(6+i)=7i2+51i+54

$(9 + 7 i) \cdot (6 + i) = 7 i^{2} + 51 i + 54$