$(8 x + 3)^{2} = 64 x^{2} + 48 x + 9$

Explanation

$(8 x + 3)^{2} \overset{◯}{1} 64 x^{2} + 48 x + 9$
①	Find $(8 x + 3)^{2}$ using formula. $(A + B)^{2} = A^{2} + 2 \cdot A \cdot B + B^{2}$ where $A = 8 x$ and $B = 3$ . $(8 x + 3)^{2} = (8 x)^{2} + 2 \cdot 8 x \cdot 3 + 3^{2} = 64 x^{2} + 48 x + 9$

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(8x+3)2=64x2+48x+9

$(8 x + 3)^{2} = 64 x^{2} + 48 x + 9$