$$ \begin{aligned}(8x+3)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}64x^2+48x+9\end{aligned} $$ | |
① | Find $ \left(8x+3\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 8x } $ and $ B = \color{red}{ 3 }$. $$ \begin{aligned}\left(8x+3\right)^2 = \color{blue}{\left( 8x \right)^2} +2 \cdot 8x \cdot 3 + \color{red}{3^2} = 64x^2+48x+9\end{aligned} $$ |