$(8 + 4 i) \cdot (11 - 3 i) = - 12 i^{2} + 20 i + 88$

Explanation

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$(8 + 4 i) \cdot (11 - 3 i) \overset{◯}{1} 88 - 24 i + 44 i - 12 i^{2} \overset{◯}{2} - 12 i^{2} + 20 i + 88$
①	Multiply each term of $(8 + 4 i)$ by each term in $(11 - 3 i)$ . $(8 + 4 i) \cdot (11 - 3 i) = 88 - 24 i + 44 i - 12 i^{2}$
②	Combine like terms: $88 - 24 i + 44 i - 12 i^{2} = - 12 i^{2} + 20 i + 88$

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(8+4i)⋅(11−3i)=−12i2+20i+88

$(8 + 4 i) \cdot (11 - 3 i) = - 12 i^{2} + 20 i + 88$