Answer
$$(8-3i)\cdot(9+6i)=-18i^2+21i+72$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(8-3i)\cdot(9+6i)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}72+48i-27i-18i^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-18i^2+21i+72\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{8-3i}\right) $ by each term in $ \left( 9+6i\right) $. $$ \left( \color{blue}{8-3i}\right) \cdot \left( 9+6i\right) = 72+48i-27i-18i^2 $$ |
| ② | Combine like terms: $$ 72+ \color{blue}{48i} \color{blue}{-27i} -18i^2 = -18i^2+ \color{blue}{21i} +72 $$ |
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