$(8 - 3 i) \cdot (6 + 2 i) = - 6 i^{2} - 2 i + 48$

Explanation

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$(8 - 3 i) \cdot (6 + 2 i) \overset{◯}{1} 48 + 16 i - 18 i - 6 i^{2} \overset{◯}{2} - 6 i^{2} - 2 i + 48$
①	Multiply each term of $(8 - 3 i)$ by each term in $(6 + 2 i)$ . $(8 - 3 i) \cdot (6 + 2 i) = 48 + 16 i - 18 i - 6 i^{2}$
②	Combine like terms: $48 + 16 i - 18 i - 6 i^{2} = - 6 i^{2} - 2 i + 48$

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(8−3i)⋅(6+2i)=−6i2−2i+48

$(8 - 3 i) \cdot (6 + 2 i) = - 6 i^{2} - 2 i + 48$