Answer
$$(7-4i)e^{(7+4i)x}+(7+4i)e^{(7-4i)x}=(7-4i)e^{7x+4ix}+(7+4i)e^{7x-4ix}$$
Explanation
| $$ \begin{aligned}(7-4i)e^{(7+4i)x}+(7+4i)e^{(7-4i)x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(7-4i)e^{7x+4ix}+(7+4i)e^{7x-4ix}\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{7+4i}\right) \cdot x = 7x+4ix $$$$ \left( \color{blue}{7-4i}\right) \cdot x = 7x-4ix $$ |
This page was created using
Complex Expression calculator