$\frac{6 + 8 i}{9} i = \frac{- 8 + 6 i}{9}$

Explanation

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$\frac{6 + 8 i}{9} i \overset{◯}{1} \frac{8 i ^{2} + 6 i}{9} \overset{◯}{2} \frac{- 8 + 6 i}{9}$
①	Multiply $\frac{6 + 8 i}{9}$ by $i$ to get $\frac{8 i ^{2} + 6 i}{9}$ . Step 1: Write $i$ as a fraction by putting $1$ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $\frac{6 + 8 i}{9} \cdot i Step 1 \frac{6 + 8 i}{9} \cdot \frac{i}{1} Step 2 \frac{( 6 + 8 i ) \cdot i}{9 \cdot 1} = Step 3 \frac{6 i + 8 i ^{2}}{9} = \frac{8 i ^{2} + 6 i}{9}$
②	$8 i^{2} = 8 \cdot (- 1) = - 8$

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$\frac{6 + 8 i}{9} i = \frac{- 8 + 6 i}{9}$